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In the process of forming crystals of Copper sulphate, it is added to boiling water with a few drops of sulphuric acid and stirred continuously. This solution on cooling down yields pure crystals. Why are the crystals not formed when the solution is hot?1 pointa. Impurities would persist at higher temperaturesb. The crystals can solidify only at room temperaturesc. Salt molecules can only precipitate at the cooler temperatured. Impurities prohibit crystal formation above room temperature

Question

In the process of forming crystals of Copper sulphate, it is added to boiling water with a few drops of sulphuric acid and stirred continuously. This solution on cooling down yields pure crystals. Why are the crystals not formed when the solution is hot?1 pointa. Impurities would persist at higher temperaturesb. The crystals can solidify only at room temperaturesc. Salt molecules can only precipitate at the cooler temperatured. Impurities prohibit crystal formation above room temperature

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Solution

The formation of crystals from a solution is a process known as crystallization. This process involves two major steps: dissolution in a solvent and then crystallization or precipitation from the solution.

In the case of Copper sulphate, when it is added to boiling water with a few drops of sulphuric acid, it dissolves in the water due to the high temperature, which increases the solubility of the Copper sulphate. This forms a solution.

When this solution is allowed to cool down, the solubility of Copper sulphate decreases. This means that the water can no longer hold the same amount of Copper sulphate in solution as it could when it was hot. As a result, the excess Copper sulphate starts to separate out from the solution.

This separated Copper sulphate then starts to form a solid structure, which we see as crystals. This is why the crystals are not formed when the solution is hot, but only when it cools down.

So, the correct answer to your question would be: c. Salt molecules can only precipitate at the cooler temperature.

This problem has been solved

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