A watch which gains uniformly, is 5 min slow at 8 o'clock in the morning on sunday and it is 5 min 48 sec fast at 8 p.m on following sunday. when was it correct?

This problem involves a watch that is gaining time uniformly. Here's how to solve it:

1. First, calculate the total time the watch has gained. The watch was 5 minutes slow at 8 AM on Sunday and 5 minutes 48 seconds fast at 8 PM on the following Sunday. This means the watch has gained a total of 5 minutes (to get to the correct time) + 5 minutes 48 seconds (the time it was fast) = 10 minutes 48 seconds.

2. Next, calculate the total time period over which the watch has been gaining time. From 8 AM on Sunday to 8 PM on the following Sunday is a total of 7 days and 12 hours = 180 hours.

3. Now, calculate the rate at which the watch is gaining time. The watch has gained 10 minutes 48 seconds over 180 hours. Convert 10 minutes 48 seconds to hours (10.8/60 = 0.18 hours). So, the watch is gaining time at a rate of 0.18 hours per 180 hours = 0.001 hours per hour.

4. The watch was correct when it had gained exactly 5 minutes (the time it was initially slow). To find out when this was, divide 5 minutes by the rate of gain. 5 minutes = 5/60 = 0.08333 hours. So, 0.08333 hours / 0.001 hours per hour = 83.33 hours.

5. Finally, add this time to the initial time of 8 AM on Sunday. 83.33 hours is approximately 3 days and 11 hours. So, the watch was showing the correct time at around 7 PM on Wednesday.

To solve this problem, we need to understand that the watch gains time uniformly. This means that the amount of time it gains per hour is constant.

1. First, calculate the total time the watch has gained. The watch was 5 minutes slow at 8 AM on Sunday and 5 minutes 48 seconds fast at 8 PM on the following Sunday. This means it has gained a total of 5 minutes (to get to the correct time) + 5 minutes 48 seconds (the amount it is fast by) = 10 minutes 48 seconds.

2. Next, calculate the total time that has passed. From 8 AM on Sunday to 8 PM on the following Sunday is 7 days and 12 hours = 180 hours.

3. Now, calculate the rate at which the watch gains time. Divide the total time gained by the total time passed to find the rate of gain per hour. (10 minutes 48 seconds) / (180 hours) = 0.036 hours/hour, or about 2.16 minutes per day.

4. Finally, calculate when the watch showed the correct time. The watch was 5 minutes slow at 8 AM on Sunday, and it gains 2.16 minutes per day. So, divide 5 minutes by 2.16 minutes/day to find out how many days it took for the watch to show the correct time. 5 / 2.16 = approximately 2.31 days.

So, the watch showed the correct time about 2.31 days after 8 AM on Sunday, which would be around 7:30 AM on Tuesday.

This problem involves a watch that is gaining time uniformly. It is 5 minutes slow at 8 AM on Sunday and 5 minutes 48 seconds fast at 8 PM on the following Sunday. We need to find out when the watch showed the correct time.

Step 1: Calculate the total time period The total time from 8 AM on Sunday to 8 PM on the following Sunday is 7 days and 12 hours, which is 180 hours.

Step 2: Calculate the total time gained The watch was initially 5 minutes slow and later it was 5 minutes 48 seconds fast. So, the total time gained is 5 minutes (initially slow) + 5 minutes 48 seconds (later fast) = 10 minutes 48 seconds = 648 seconds.

Step 3: Calculate the rate of gaining time Since the watch is gaining time uniformly, the rate of gaining time is total time gained / total time period = 648 seconds / 180 hours = 3.6 seconds per hour.

Step 4: Calculate when the watch showed the correct time The watch was 5 minutes slow initially, which is 300 seconds. So, the time it takes for the watch to show the correct time is 300 seconds / 3.6 seconds per hour = 83.33 hours.

So, the watch showed the correct time 83.33 hours after 8 AM on Sunday. This is 3 days and 11.33 hours, which is approximately 3 days and 20 minutes. So, the watch showed the correct time at around 8:20 AM on Wednesday.

To solve this problem, we need to understand that the watch gains time uniformly. This means that the amount of time it gains per hour is constant.

1. First, calculate the total time the watch has gained. The watch was 5 minutes slow at 8 AM on Sunday and 5 minutes 48 seconds fast at 8 PM on the following Sunday. This means it has gained a total of 5 minutes (to get to the correct time) + 5 minutes 48 seconds (the amount it is fast by) = 10 minutes 48 seconds.

2. Next, calculate the total time that has passed. From 8 AM on Sunday to 8 PM on the following Sunday is 7 days and 12 hours, or 180 hours.

3. Now, calculate the rate at which the watch gains time. Divide the total time gained by the total time passed to find the rate of gain per hour. Convert 10 minutes 48 seconds to seconds for easier calculation. 10 minutes 48 seconds = 648 seconds. So, the watch gains 648 seconds / 180 hours = 3.6 seconds per hour.

4. Finally, calculate when the watch showed the correct time. The watch was 5 minutes slow at 8 AM on Sunday, and it gains 3.6 seconds every hour. To find out when the watch was correct, divide the amount of time it was slow by the rate of gain. 5 minutes = 300 seconds. So, 300 seconds / 3.6 seconds per hour = approximately 83.33 hours.

5. Add this time to the initial time of 8 AM on Sunday. 83.33 hours is approximately 3 days and 11 hours. So, the watch showed the correct time at around 7 PM on Wednesday.

To solve this problem, we need to understand that the watch gains time uniformly. This means that the amount of time it gains per hour is constant.

1. First, calculate the total time the watch has gained. The watch was 5 minutes slow at 8 AM on Sunday and 5 minutes 48 seconds fast at 8 PM on the following Sunday. This means it has gained a total of 5 minutes (to get to the correct time) + 5 minutes 48 seconds (the amount it is fast by) = 10 minutes 48 seconds.

2. Next, calculate the total time that has passed. From 8 AM on Sunday to 8 PM on the following Sunday is a total of 7 days and 12 hours = 180 hours.

3. Now, calculate the rate at which the watch gains time. Divide the total time gained by the total time passed to find the rate of gain per hour. (10 minutes 48 seconds) / (180 hours) = approximately 0.06 minutes per hour, or about 3.6 seconds per hour.

4. Finally, calculate when the watch showed the correct time. The watch was 5 minutes slow at 8 AM on Sunday, and it gains approximately 3.6 seconds every hour. So, to find out when it showed the correct time, divide the amount of time it was slow by the rate of gain per hour. (5 minutes) / (0.06 minutes per hour) = approximately 83.33 hours.

5. Add this time to the initial time of 8 AM on Sunday. 83.33 hours is approximately 3 days and 11 hours. So, the watch showed the correct time at around 7 PM on Wednesday.