The answer is: the voltage stays the same, but the charge increases. Here's why:

1. The voltage across a capacitor is determined by the battery to which it is connected. Since the capacitor stays connected to the battery and the battery voltage doesn't change, the voltage across the capacitor doesn't change either. So, options 1 and 2 are incorrect.

2. The charge on a capacitor is given by the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage. When the plate spacing is doubled, the capacitance C is halved (because capacitance is inversely proportional to the distance between the plates). However, since the voltage V doesn't change, the charge Q = CV doesn't change either. So, options 3 and 4 are incorrect.

3. Since neither the voltage nor the charge changes, option 5 is also incorrect.

So, none of the options given are correct. The voltage stays the same and the charge doesn't change when the plate spacing of a parallel plate capacitor is doubled.

Question

The answer is: the voltage stays the same, but the charge increases. Here's why:

1. The voltage across a capacitor is determined by the battery to which it is connected. Since the capacitor stays connected to the battery and the battery voltage doesn't change, the voltage across the capacitor doesn't change either. So, options 1 and 2 are incorrect.

2. The charge on a capacitor is given by the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage. When the plate spacing is doubled, the capacitance C is halved (because capacitance is inversely proportional to the distance between the plates). However, since the voltage V doesn't change, the charge Q = CV doesn't change either. So, options 3 and 4 are incorrect.

3. Since neither the voltage nor the charge changes, option 5 is also incorrect.

So, none of the options given are correct. The voltage stays the same and the charge doesn't change when the plate spacing of a parallel plate capacitor is doubled.

Knowee AI · Accepted Answer

The answer is: the voltage stays the same, but the charge increases. Here's why:

1. The voltage across a capacitor is determined by the battery to which it is connected. Since the capacitor stays connected to the battery and the battery voltage doesn't change, the voltage across the capacitor doesn't change either. So, options 1 and 2 are incorrect.

2. The charge on a capacitor is given by the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage. When the plate spacing is doubled, the capacitance C is halved (because capacitance is inversely proportional to the distance between the plates). However, since the voltage V doesn't change, the charge Q = CV doesn't change either. So, options 3 and 4 are incorrect.

3. Since neither the voltage nor the charge changes, option 5 is also incorrect.

So, none of the options given are correct. The voltage stays the same and the charge doesn't change when the plate spacing of a parallel plate capacitor is doubled.

A parallel plate capacitor initially has a voltage of 400V, and stays connected to a battery. If the plate spacing is doubled, what happens? 1. the voltage decreases 2. the voltage increases 3. the charge decreases 4. the charge increases 5. both voltage and charge change

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