The number of turns in the primary and secondary coils of a transformer are 5 and 10 respectively. The mutual inductance is 25 H. If the number of turns in the primary and secondary coils are changed to 10 and 5 respectively, then the mutual inductance (in henry) will be :-6.2512.52550

In an ideal transformer, what is the relationship between the number of turns in the primary coil (N1) and the number of turns in the secondary coil (N2)?a.N1 < N2b.N1 = N2c.No relationshipd.N1 > N2

Define the mutual-inductance of two coils. Write its formula. Also define its SIunit

The diagram below represents a voltage step-down transformer with 1000 turns on the primary coil and 100 turns on the secondary. The primary is connected to a 10 V AC supply and a 10 Ω resistor is connected across the secondary. You may assume that the transformer is ideal, i.e. there are no flux or other losses. The current flowing in the primary circuit is to one decimal place in mA:

A thin coil has 10 rectangular turns of wire. When a current of 2.00 A runs through the coil, there is a total flux of 0.005 T-m2 enclosed by one turn of the coil (note that the inductance is the proportionality constant between current and magnetic flux). What is the total inductance in Henries?

Define mutual inductance (M) and self-inductance (L), and their unit henry