Which of the following will give output as [23,2,9,75] ?If list1=[6,23,3,2,0,9,8,75]print(list1[1:7:2])print(list1[0:7:2])print(list1[1:8:2])print(list1[0:8:2])

The correct answer is print(list1[1:8:2]).

Here's the step by step explanation:

1. In Python, list slicing is done in the format list[start:stop:step]. The start index is inclusive and stop index is exclusive. The step is the increment between each index for slicing.

2. list1[1:8:2] means start at index 1 (23), stop at index 8 (which is exclusive, so it stops at index 7), and step by 2 (skip every other element).

3. So, it starts at index 1 (23), skips index 2 (3), takes index 3 (2), skips index 4 (0), takes index 5 (9), skips index 6 (8), and takes index 7 (75).

4. Therefore, print(list1[1:8:2]) will output [23,2,9,75].

The correct answer is print(list1[1:8:2]).

Here's the step by step explanation:

1. The slicing operation in Python is in the format list[start:stop:step]. start is the index where the slice starts (inclusive), stop is the index where the slice ends (exclusive), and step is the amount by which the index increases/decreases.

2. In the given list list1=[6,23,3,2,0,9,8,75], we want to get the output as [23,2,9,75].

3. If we look at the options:

   • print(list1[1:7:2]) will start at index 1 (23), stop at index 7 (exclusive, so it stops at 8), and step by 2. So it will print [23, 2, 9].

   • print(list1[0:7:2]) will start at index 0 (6), stop at index 7 (exclusive, so it stops at 8), and step by 2. So it will print [6, 3, 0, 8].

   • print(list1[1:8:2]) will start at index 1 (23), stop at index 8 (exclusive, so it stops at 75), and step by 2. So it will print [23, 2, 9, 75].

   • print(list1[0:8:2]) will start at index 0 (6), stop at index 8 (exclusive, so it stops at 75), and step by 2. So it will print [6, 3, 0, 8].

So, the correct answer is print(list1[1:8:2]).