Example 1: Calculate the hardness of water sample having following analysis : Mg(HCO3)2 = 7.3ppm, Ca(HCO3)2 = 16.2 ppm, MgCl2 = 9.5 ppm, CaSO4 = 13.6 ppm, Fe2O3 = 8.5 ppm, Mg(NO3)2=14.8 ppm. Also calculate carbonate and non carbonate hardnes

Calculate the hardness in terms of CaCO3 Equivalent if 16.8mg/l   Mg (HCO3)2  is present in water sample.a.40 mg/lb.16.8 mg/lc.11 mg/ld.11.5 mg/l

Calculate the total hardness of water in °Fr and °Cl from the following analysis of water sample. Mg(HCO3)2=20.8 mg/L, Mg(NO3)2=28.8 mg/L, MgCl2=21.0 mg/L, MgSO4=20 mg/L, CaCO3=21.2 mg/L, KCl=73.2 mg/L

You want to test for hardness of water but hard water is not available inthe laboratory. Which of the following compounds may be dissolved inpure water to make it hard ?(i) Hydrogen Carbonate of Sodium(ii) Sulphate of Magnesium(iii) Chloride of Calcium(iv) Carbonate of Sodium

Calculate the temporary hardness and permanent hardness of a sample of water containing: Mg(HCO3)2 =7.3 mg/L; Ca(HCO3)2 = 16.2 mg/L; MgCl2 = 9.5 mg/L; CaSO4 = 13.6 mg/LMolecular weights: Ca(HCO3)2 = 162; Mg(HCO3)2=146; CaSO4= 136; MgSO4 = 120; MgCl2 = 95; Al2(SO4)3 = 114;Ca(NO3)2=164

Calculate the total and permanent hardness in ppm in given water sample:1. 50 mL of standard hard water, containing 1 mg, pure CaCo3 per mL, consumed 20 mL EDTA solution.2. 50 mL of the water sample consumed 30 mL EDTA solution using EBT indiactor.3. 50 ml of the water sample after boiling and filtering consumed 10 mL of EDTA solution.