It takes 100 J to raise the temperature of 14.4 g of ortho-carborane by 6.7 oC. What is the molar heat capacity of ortho-carborane if its molecular formula is C2B10H12 (MW = 144.44)? Give your answer in J/K.mol to 1 d.p
Question
It takes 100 J to raise the temperature of 14.4 g of ortho-carborane by 6.7 oC. What is the molar heat capacity of ortho-carborane if its molecular formula is C2B10H12 (MW = 144.44)? Give your answer in J/K.mol to 1 d.p
Solution
Sure, here's how to calculate the molar heat capacity:
Step 1: Calculate the amount of heat absorbed per gram. This is done by dividing the total heat absorbed by the mass of the substance. In this case, it's 100 J / 14.4 g = 6.94 J/g°C.
Step 2: Calculate the amount of heat absorbed per mole. This is done by multiplying the heat absorbed per gram by the molar mass of the substance. In this case, it's 6.94 J/g°C * 144.44 g/mol = 1002.93 J/mol°C.
Step 3: Since the temperature change is 6.7°C, we divide the heat absorbed per mole by the temperature change to get the molar heat capacity. In this case, it's 1002.93 J/mol°C / 6.7°C = 149.7 J/K.mol.
So, the molar heat capacity of ortho-carborane is 149.7 J/K.mol to 1 decimal place.
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