Knowee
Questions
Features
Study Tools

Suppose that a volcano is erupting and readings of the rate r(t) at which solid materials are spewed into the atmosphere are given in the table. The time t is measured in seconds and the units for r(t) are tonnes (metric tons) per second. (Use 6 equal subintervals.)t 0 1 2 3 4 5 6r(t) 2 8 20 32 46 52 60(a) Give upper and lower estimates for the total quantity Q(6) of erupted materials after 6 seconds.Q(6) = tonnes (lower estimate)Q(6) = tonnes (upper estimate)(b) Use the Midpoint Rule to estimate Q(6). (Use 3 equal subintervals.)Q(6) = tonnes

Question

Suppose that a volcano is erupting and readings of the rate r(t) at which solid materials are spewed into the atmosphere are given in the table. The time t is measured in seconds and the units for r(t) are tonnes (metric tons) per second. (Use 6 equal subintervals.)t 0 1 2 3 4 5 6r(t) 2 8 20 32 46 52 60(a) Give upper and lower estimates for the total quantity Q(6) of erupted materials after 6 seconds.Q(6) = tonnes (lower estimate)Q(6) = tonnes (upper estimate)(b) Use the Midpoint Rule to estimate Q(6). (Use 3 equal subintervals.)Q(6) = tonnes

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

(a) To estimate the total quantity Q(6) of erupted materials after 6 seconds, we can use the concept of Riemann sums to approximate the area under the curve.

For the lower estimate, we use the left endpoints of each subinterval. The width of each subinterval is 1 second. So, the lower estimate is:

Q(6) = r(0) + r(1) + r(2) + r(3) + r(4) + r(5) = 2 + 8 + 20 + 32 + 46 + 52 = 160 tonnes

For the upper estimate, we use the right endpoints of each subinterval. So, the upper estimate is:

Q(6) = r(1) + r(2) + r(3) + r(4) + r(5) + r(6) = 8 + 20 + 32 + 46 + 52 + 60 = 218 tonnes

(b) To use the Midpoint Rule, we need to divide the interval [0,6] into 3 equal subintervals: [0,2], [2,4], and [4,6]. The midpoints of these subintervals are 1, 3, and 5. So, the Midpoint Rule gives us:

Q(6) = 2*(r(1) + r(3) + r(5)) = 2*(8 + 32 + 52) = 184 tonnes

So, the lower estimate for Q(6) is 160 tonnes, the upper estimate is 218 tonnes, and the Midpoint Rule estimate is 184 tonnes.

This problem has been solved

Similar Questions

Oil leaked from a tank at a rate of r(t) liters per hour. The rate decreased as time passed, and values of the rate at two hour time intervals are shown in the table. Find lower and upper estimates for the total amount of oil that leaked out.V ≈ L (lower estimate)V ≈ L (upper estimate)t (h) 0 2 4 6 8 10r(t) (L/h) 8.7 7.9 6.7 6.2 5.7 5.1

Which one of the following is a valid conclusion from this histogram?The median time between eruptions is between 70 and 80 minutesThe distribution of times between eruptions is roughly log normalShorter intervals between eruptions are more likely than longer intervalsThe geyser has two sources erupting at different rates

A chemistry graduate student is studying the rate of this reaction:→2NH3g+N2g3H2gHe fills a reaction vessel with NH3 and measures its concentration as the reaction proceeds:time(seconds) NH30 0.0300M0.10 0.00957M0.20 0.00569M0.30 0.00405M0.40 0.00314MUse this data to answer the following questions.Write the rate law for this reaction. rate =k Calculate the value of the rate constant k.Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol. =k

A student has been asked the following question:A 2.5 kW cement mixer provides 50 kJ of work mixing the raw materials.Calculate the time the cement mixer was on for.They carried out their calculation using the following steps:P = 2.5 kW = 2500 WW = 50 kJ = 50 000 JP = W / t2500 = 50 000 / t2500 x t = 50 000t = 50 000 / 2500t = 20 minutesHas this been answered correctly?They made an error when rearranging the equation.This has been calculated correctly, but they used incorrect units.This has been calculated and answered correctly.This has been calculated incorrectly due to misreading the numbers in the question.They did not convert kilowatts into watts.

For the gaseous reaction 2A + B → C + D,rate = k[A][B]. The volume of the containercontaining the reaction mixture is suddenlyreduced to one fourth of its original volume.New rate with respect to original rate is :

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.