Colorblindness is a sex-linked trait that is carried on the X chromosome. Males have one X and one Y chromosome (XY), while females have two X chromosomes (XX).

A colorblind male would have the colorblindness gene on his only X chromosome (XcY). A carrier female would have one normal X chromosome and one with the colorblindness gene (XCXc).

When they have children, each parent passes on one of their X chromosomes to their daughters. The father can only pass on his Xc, while the mother has a 50% chance of passing on either XC or Xc.

This results in two possible combinations for their daughters:

1. The daughter inherits the father's Xc and the mother's XC, resulting in a carrier female with normal vision (XCXc).
2. The daughter inherits the father's Xc and the mother's Xc, resulting in a colorblind female (XcXc).

So, there is a 50% chance that a daughter will have normal vision and be a carrier, and a 50% chance that a daughter will be colorblind. Therefore, 50% of their female offspring will have normal vision.

Question

Colorblindness is a sex-linked trait that is carried on the X chromosome. Males have one X and one Y chromosome (XY), while females have two X chromosomes (XX).

A colorblind male would have the colorblindness gene on his only X chromosome (XcY). A carrier female would have one normal X chromosome and one with the colorblindness gene (XCXc).

When they have children, each parent passes on one of their X chromosomes to their daughters. The father can only pass on his Xc, while the mother has a 50% chance of passing on either XC or Xc.

This results in two possible combinations for their daughters:

1. The daughter inherits the father's Xc and the mother's XC, resulting in a carrier female with normal vision (XCXc). 
2. The daughter inherits the father's Xc and the mother's Xc, resulting in a colorblind female (XcXc).

So, there is a 50% chance that a daughter will have normal vision and be a carrier, and a 50% chance that a daughter will be colorblind. Therefore, 50% of their female offspring will have normal vision.

Knowee AI · Accepted Answer

Colorblindness is a sex-linked trait that is carried on the X chromosome. Males have one X and one Y chromosome (XY), while females have two X chromosomes (XX).

A colorblind male would have the colorblindness gene on his only X chromosome (XcY). A carrier female would have one normal X chromosome and one with the colorblindness gene (XCXc).

When they have children, each parent passes on one of their X chromosomes to their daughters. The father can only pass on his Xc, while the mother has a 50% chance of passing on either XC or Xc.

This results in two possible combinations for their daughters:

1. The daughter inherits the father's Xc and the mother's XC, resulting in a carrier female with normal vision (XCXc). 
2. The daughter inherits the father's Xc and the mother's Xc, resulting in a colorblind female (XcXc).

So, there is a 50% chance that a daughter will have normal vision and be a carrier, and a 50% chance that a daughter will be colorblind. Therefore, 50% of their female offspring will have normal vision.

A male who is colorblind marries a woman who is a carrier for colorblindness, but has normal vision. What percentage of their female offspring will have normal vision?

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