What correction should be made to the following code to calculate the Fibonacci number correctly?def fib(n): return fib(n-1) + fib(n-2)
Question
What correction should be made to the following code to calculate the Fibonacci number correctly?def fib(n): return fib(n-1) + fib(n-2)
Solution
The code provided is a recursive function to calculate the Fibonacci number, but it lacks a base case. Without a base case, the function will keep calling itself indefinitely, leading to a stack overflow error.
Here's the corrected code:
def fib(n):
if n <= 0:
return "Input should be a positive integer."
elif n == 1:
return 0
elif n == 2:
return 1
else:
return fib(n-1) + fib(n-2)
In this corrected code, we have added base cases for n == 1 and n == 2. When n == 1, the function returns 0 and when n == 2, it returns 1. These are the first two numbers in the Fibonacci sequence.
We also added a condition to check if n is less than or equal to 0. If it is, the function returns an error message. This is because the Fibonacci sequence is not defined for non-positive integers.
Similar Questions
which of the following program generates a Fibonacci sequence of length 28?A. def Fibo(n): if n<=1: return n else: return (Fibo(n-1)+Fibo(n-2)) n= input("Enter number of terms: ")if n<=0: print(" Check the number entered ")elif:n != 28 print("No sequence ")else: for i in range(n): print(Fibo(i))B. def Fibo(n): if n<=1: return n else: return (Fibo(n-1)+Fibo(n-2)) n= input("Enter number of terms: ")if n<=0: print(" Check the number entered ")else: print("The required sequence is ") for i in range(n): print(Fibo(i))C. def Fibo(n): if n<=1: return n else: return (Fibo(n-1)+Fibo(n-2)) n= int(input("Enter number of terms: "))#n= t//2if n<=0: print(" Check the number entered ")else: print("The required sequence is ") for i in range(28): print(Fibo(i)) D. def Fibo(n): if n<=1: return n else: return (Fibo(n-1)+Fibo(n-2)) n=int input("Enter number of terms: ")if n<=0: print(" Check the number entered ")else: print("The required sequence is ") for i in range(28): print(Fibo(i))
Consider the recursive implementation to find the nth fibonacci number:int fibo(int n) if n <= 1 return n return __________ Which line would make the implementation complete? fibo(n) + fibo(n) fibo(n) + fibo(n – 1) fibo(n – 1) + fibo(n + 1) fibo(n – 1) + fibo(n – 2)
A Fibonacci sequence is a sequence of numbers (called Fibonacci numbers)in which each number is the sum of the two preceding ones as following:1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, .
A Fibonacci sequence is a sequence of numbers (called Fibonacci numbers) in which each number is the sum of the two preceding ones as following: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, ... The task is to implement two functions in C a) using recursive function style, F(n) = F(n − 1) + F(n − 2) when n ≥ 2, F(0) = 0, F(1) = 1.
The Fibonacci sequence is F(n) = F(n – 1) + F(n – 2).If F(8) = 21 and F(9) = 34, which of the following is true?A.F(10) = 55B.F(13) = 21C.F(10) = 53D.F(17) = 55
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