To find the density of the hydrogen gas, we can use the ideal gas law equation, which is:

PV = nRT

Where:
P is the pressure,
V is the volume,
n is the number of moles,
R is the ideal gas constant, and
T is the temperature.

We want to find the density (ρ), which is mass/volume. We can express the number of moles (n) as mass (m) divided by molar mass (M), so the equation becomes:

PV = (m/M)RT

Rearranging for m/V (which is ρ), we get:

ρ = PM/RT

We know that:
P = 249 kPa = 249,000 Pa (since 1 kPa = 1,000 Pa),
R = 8.314 J/(mol·K) (the ideal gas constant),
T = 27°C = 300.15 K (since you add 273.15 to convert from Celsius to Kelvin), and
M = 2.016 g/mol (the molar mass of hydrogen).

Substituting these values into the equation, we get:

ρ = (249,000 Pa * 2.016 g/mol) / (8.314 J/(mol·K) * 300.15 K)

Solving this equation will give you the density of the hydrogen gas in the cylinder.

Question

To find the density of the hydrogen gas, we can use the ideal gas law equation, which is:

PV = nRT

Where:
P is the pressure,
V is the volume,
n is the number of moles,
R is the ideal gas constant, and
T is the temperature.

We want to find the density (ρ), which is mass/volume. We can express the number of moles (n) as mass (m) divided by molar mass (M), so the equation becomes:

PV = (m/M)RT

Rearranging for m/V (which is ρ), we get:

ρ = PM/RT

We know that:
P = 249 kPa = 249,000 Pa (since 1 kPa = 1,000 Pa),
R = 8.314 J/(mol·K) (the ideal gas constant),
T = 27°C = 300.15 K (since you add 273.15 to convert from Celsius to Kelvin), and
M = 2.016 g/mol (the molar mass of hydrogen).

Substituting these values into the equation, we get:

ρ = (249,000 Pa * 2.016 g/mol) / (8.314 J/(mol·K) * 300.15 K)

Solving this equation will give you the density of the hydrogen gas in the cylinder.

Knowee AI · Accepted Answer

To find the density of the hydrogen gas, we can use the ideal gas law equation, which is:

PV = nRT

Where:
P is the pressure,
V is the volume,
n is the number of moles,
R is the ideal gas constant, and
T is the temperature.

We want to find the density (ρ), which is mass/volume. We can express the number of moles (n) as mass (m) divided by molar mass (M), so the equation becomes:

PV = (m/M)RT

Rearranging for m/V (which is ρ), we get:

ρ = PM/RT

We know that:
P = 249 kPa = 249,000 Pa (since 1 kPa = 1,000 Pa),
R = 8.314 J/(mol·K) (the ideal gas constant),
T = 27°C = 300.15 K (since you add 273.15 to convert from Celsius to Kelvin), and
M = 2.016 g/mol (the molar mass of hydrogen).

Substituting these values into the equation, we get:

ρ = (249,000 Pa * 2.016 g/mol) / (8.314 J/(mol·K) * 300.15 K)

Solving this equation will give you the density of the hydrogen gas in the cylinder.

A cylinder contains hydrogen gas at pressure of 249 kPa and temperature 27OC. Its density is :

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