Sure, I understand that you want a step-by-step solution to the problem. Here it is:

1. First, we need to get two numbers as input. Let's call them num1 and num2.

2. Next, we need to calculate the absolute difference between each number and 50. We can use the abs() function for this. Let's call these differences diff1 and diff2.

3. Now, we need to compare diff1 and diff2. If diff1 is less than diff2, then num1 is closer to 50. If diff2 is less than diff1, then num2 is closer to 50.

4. If diff1 and diff2 are equal, then both numbers are equally close to 50. In this case, we need to print 0.

5. Finally, we print the number that is closer to 50.

Here is a pseudo code for the above steps:

```
get num1 and num2
calculate diff1 = abs(50 - num1)
calculate diff2 = abs(50 - num2)
if diff1

Question

Sure, I understand that you want a step-by-step solution to the problem. Here it is:

1. First, we need to get two numbers as input. Let's call them num1 and num2.

2. Next, we need to calculate the absolute difference between each number and 50. We can use the abs() function for this. Let's call these differences diff1 and diff2.

3. Now, we need to compare diff1 and diff2. If diff1 is less than diff2, then num1 is closer to 50. If diff2 is less than diff1, then num2 is closer to 50.

4. If diff1 and diff2 are equal, then both numbers are equally close to 50. In this case, we need to print 0.

5. Finally, we print the number that is closer to 50.

Here is a pseudo code for the above steps:

```
get num1 and num2
calculate diff1 = abs(50 - num1)
calculate diff2 = abs(50 - num2)
if diff1 < diff2 then print num1
else if diff2 < diff1 then print num2
else print 0
```

This is a simple solution to the problem. You can implement this in any programming language of your choice.

Knowee AI · Accepted Answer

Sure, I understand that you want a step-by-step solution to the problem. Here it is:

1. First, we need to get two numbers as input. Let's call them num1 and num2.

2. Next, we need to calculate the absolute difference between each number and 50. We can use the abs() function for this. Let's call these differences diff1 and diff2.

3. Now, we need to compare diff1 and diff2. If diff1 is less than diff2, then num1 is closer to 50. If diff2 is less than diff1, then num2 is closer to 50.

4. If diff1 and diff2 are equal, then both numbers are equally close to 50. In this case, we need to print 0.

5. Finally, we print the number that is closer to 50.

Here is a pseudo code for the above steps:

```
get num1 and num2
calculate diff1 = abs(50 - num1)
calculate diff2 = abs(50 - num2)
if diff1 < diff2 then print num1
else if diff2 < diff1 then print num2
else print 0
```

This is a simple solution to the problem. You can implement this in any programming language of your choice.

The output prints the number closer to 50. If both numbers are equally close to 50, print 0.

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