The result of the code will be "5". Here's the step by step explanation: 1. An array of integers `

What is the result of the following code?#include <stdio.h>int main() { int arr[5] = {1, 2, 3, 4, 5}; int ptr = (int )(&arr + 1); printf("%d\n", *(ptr - 1)); return 0;}

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What is the result of the following code?#include <stdio.h>int main() { int arr[5] = {1, 2, 3, 4, 5}; int *ptr = (int *)(&arr + 1); printf("%d\n", *(ptr - 1)); return 0;}

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The result of the code will be "5".

Here's the step by step explanation:

An array of integers `

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What is the result of the following code?#include <stdio.h>int main() { int arr[5] = {1, 2, 3, 4, 5}; int *ptr = (int *)(&arr + 1); printf("%d\n", *(ptr - 1)); return 0;}

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What is the result of the following code?#include <stdio.h>int main() { int arr[5] = {1, 2, 3, 4, 5}; int ptr = (int )(&arr + 1); printf("%d\n", *(ptr - 1)); return 0;}