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A substance with water equivalent of 6 grams get 10 °C increase in temperature calculate heat absorbed by substance :

Question

A substance with water equivalent of 6 grams get 10 °C increase in temperature calculate heat absorbed by substance :

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Solution

To calculate the heat absorbed by the substance, we can use the formula for heat transfer:

Q = m * c * ΔT

where: Q = heat absorbed, m = mass of the substance, c = specific heat capacity, ΔT = change in temperature.

In this case, we are given the water equivalent of the substance, not its mass. The water equivalent is the amount of water that would absorb or release the same amount of heat as the substance for the same change in temperature. So, we can use the water equivalent as the mass in our calculation.

We also know that the specific heat capacity of water is approximately 4.18 J/g°C.

So, we can plug in the values:

Q = 6 g * 4.18 J/g°C * 10 °C = 250.8 J

So, the substance absorbed 250.8 Joules of heat.

This problem has been solved

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