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A bulb is rated at 330V- 110W. What do you think is its resistance?

Question

A bulb is rated at 330V- 110W. What do you think is its resistance?

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Solution

To find the resistance of the bulb, we can use Ohm's Law, which states that resistance (R) is equal to voltage (V) divided by current (I).

First, we need to find the current flowing through the bulb. We can use the formula P = IV, where P is the power in watts, I is the current in amperes, and V is the voltage in volts.

Given that the power of the bulb is 110W and the voltage is 330V, we can rearrange the formula to solve for current:

I = P / V

Substituting the values, we get:

I = 110W / 330V

I = 0.333 A

Now that we have the current, we can calculate the resistance using Ohm's Law:

R = V / I

Substituting the values, we get:

R = 330V / 0.333 A

R = 990 ohms

Therefore, the resistance of the bulb is 990 ohms.

This problem has been solved

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