Let ๐(๐ฅ, ๐ฆ) = เต0, ๐ฅ ๐ฆ = 01, ๐ฅ ๐ฆ โ 0(a) Find the limit of ๐ as (๐ฅ, ๐ฆ) approaches (0, 0) along the line ๐ฆ = ๐ฅ.(b) Prove that ๐ is not continuous at the origin.(c) Show that both partial derivatives ๐เฏซ and ๐เฏฌ exist at the origin
Question
Let ๐(๐ฅ, ๐ฆ) = เต0, ๐ฅ ๐ฆ = 01, ๐ฅ ๐ฆ โ 0(a) Find the limit of ๐ as (๐ฅ, ๐ฆ) approaches (0, 0) along the line ๐ฆ = ๐ฅ.(b) Prove that ๐ is not continuous at the origin.(c) Show that both partial derivatives ๐เฏซ and ๐เฏฌ exist at the origin
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(x)=โงโฉโจโชโชโชโช|x+1|,1,x+1โโ1x,x<0x=0x>0.๐(๐ฅ)={|๐ฅ+1|,๐ฅ<01,๐ฅ=0๐ฅ+1โ1๐ฅ,๐ฅ>0. Which of the following is/are incorrect?Question 1Answera.f(x)๐(๐ฅ) is continuous at x=0๐ฅ=0.b.f(x)๐(๐ฅ) is continuous for all real numbers x๐ฅ.ย c.f(x)๐(๐ฅ) is differentiable at x=0๐ฅ=0.d.f(x)๐(๐ฅ) is differentiable at all real numbers x๐ฅ.
Identify the statement that is FALSE:If a function ๐ is continuous on (๐,๐), then ๐ always has an absolute minimum on (๐,๐).If a function ๐ is continuous on [๐,๐], then ๐ always has an absolute minimum on [๐,๐].If a function ๐ is continuous on [๐,๐] and ๐ has no relative extrema in (๐,๐), then the absolute maximum of ๐ on [๐,๐] exists and occurs at either ๐ฅ=๐ or ๐ฅ=๐.If a function ๐ has an absolute minimum value on (๐,๐), then there is a critical point of ๐ in (๐,๐).
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Ifย โfโx=0โ๐โ๐ฅ=0,ย the function f(x,y)๐(๐ฅ,๐ฆ)ย has no dependence on the variableย x๐ฅ.Select one:TrueFalse
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