Write half-equations for the following elements forming ions, and write if it is an oxidation or a reduction half-equation: franciumbrominesulfurlithiumhydrogencopper (I)seleniummanganese (III)iodinemagnesium

1. Francium (Fr) forms Fr+ ion by losing one electron. This is an oxidation half-equation: Fr -> Fr+ + e-

2. Bromine (Br2) forms Br- ion by gaining one electron. This is a reduction half-equation: Br2 + 2e- -> 2Br-

3. Sulfur (S) forms S2- ion by gaining two electrons. This is a reduction half-equation: S + 2e- -> S2-

4. Lithium (Li) forms Li+ ion by losing one electron. This is an oxidation half-equation: Li -> Li+ + e-

5. Hydrogen (H2) forms H+ ion by losing one electron. This is an oxidation half-equation: H2 -> 2H+ + 2e-

6. Copper (I) (Cu) forms Cu+ ion by losing one electron. This is an oxidation half-equation: Cu -> Cu+ + e-

7. Selenium (Se) forms Se2- ion by gaining two electrons. This is a reduction half-equation: Se + 2e- -> Se2-

8. Manganese (III) (Mn) forms Mn3+ ion by losing three electrons. This is an oxidation half-equation: Mn -> Mn3+ + 3e-

9. Iodine (I2) forms I- ion by gaining one electron. This is a reduction half-equation: I2 + 2e- -> 2I-

10. Magnesium (Mg) forms Mg2+ ion by losing two electrons. This is an oxidation half-equation: Mg -> Mg2+ + 2e-

Francio (Fr): Fr → Fr⁺ + e⁻ (oxidación)

Bromo (Br): Br₂ + 2e⁻ → 2Br⁻ (reducción)

Azufre (S): S + 2e⁻ → S²⁻ (reducción)

Litio (Li): Li → Li⁺ + e⁻ (oxidación)

Hidrógeno (H): H₂ → 2H⁺ + 2e⁻ (oxidación)

Cobre (I) (Cu): Cu → Cu⁺ + e⁻ (oxidación)

Selenio (Se): Se + 2e⁻ → Se²⁻ (reducción)

Manganeso (III) (Mn): Mn³⁺ + 3e⁻ → Mn (reducción)

Yodo (I): I₂ + 2e⁻ → 2I⁻ (reducción)

Magnesio (Mg): Mg → Mg²⁺ + 2e⁻ (oxidación)