The problem is asking to count the frequency of all numbers from 1 to n in the given array. The array can contain integers from 1 to p and elements can be repeated or can be absent from the array. The task is to modify the array in-place such that arr[i] = frequency(i) and assume 1-based indexing. The elements greater than n in the array can be ignored for counting.

Here is a step by step solution:

1. Initialize a new array of size n+1 to all zeros. This will be used to store the frequency of each number.

2. Traverse the given array from start to end.

3. For every element in the array, if it is less than or equal to n, increment the count of that number in the new array.

4. Now, the new array contains the frequency of all numbers from 1 to n.

5. Finally, copy the new array to the original array.

Here is the Python code for the above steps:

```python
def frequencyCount(arr, n, p):
freq = [0]*(n+1)
for i in range(n):
if arr[i]

Question

The problem is asking to count the frequency of all numbers from 1 to n in the given array. The array can contain integers from 1 to p and elements can be repeated or can be absent from the array. The task is to modify the array in-place such that arr[i] = frequency(i) and assume 1-based indexing. The elements greater than n in the array can be ignored for counting.

Here is a step by step solution:

1. Initialize a new array of size n+1 to all zeros. This will be used to store the frequency of each number.

2. Traverse the given array from start to end.

3. For every element in the array, if it is less than or equal to n, increment the count of that number in the new array.

4. Now, the new array contains the frequency of all numbers from 1 to n.

5. Finally, copy the new array to the original array.

Here is the Python code for the above steps:

```python
def frequencyCount(arr, n, p):
    freq = [0]*(n+1)
    for i in range(n):
        if arr[i] <= n:
            freq[arr[i]] += 1
    for i in range(1, n+1):
        arr[i-1] = freq[i]
```

This function takes the array arr, and integers n, and p as input parameters and modify the array in-place to denote the frequency count of each element from 1 to N. The time complexity of this function is O(N) and it uses O(1) auxiliary space.

Knowee AI · Accepted Answer