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The correct answer is:  The train takes 3 seconds to pass the signal post. See the diagram below that shows the motion of the train.  The star shows the front (engine) of the train.The time of passing starts from time T2T 2​ and lasts till time T3T 3​ . Let this time be = T3T 3​ - T2T 2​ = T seconds.Then the distance moved by the engine (star on the train) during the passing time is = 20 m/s ×× T seconds = 20T metersBut from the diagram it is clear that this distance is the length of the train = 60 meters. So:  20 ×× T =  60  ⇒⇒  T = 3 seconds.

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The correct answer is:  The train takes 3 seconds to pass the signal post. See the diagram below that shows the motion of the train.  The star shows the front (engine) of the train.The time of passing starts from time T2T 2​ and lasts till time T3T 3​ . Let this time be = T3T 3​ - T2T 2​ = T seconds.Then the distance moved by the engine (star on the train) during the passing time is = 20 m/s ×× T seconds = 20T metersBut from the diagram it is clear that this distance is the length of the train = 60 meters. So:  20 ×× T =  60  ⇒⇒  T = 3 seconds.

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