In hybridization, Tt × tt gives riseto the progeny of ratio

The cross between Tt (heterozygous) and tt (homozygous recessive) in hybridization is a simple Punnett square problem. Here's how you solve it:

1. First, write down the genotypes of the parents: Tt and tt.

2. Next, set up a Punnett square. This is a 2x2 grid.

3. Write the alleles (different forms of a gene, in this case T and t) for one parent along the top of the square (T and t from Tt) and the alleles for the other parent down the left side (t and t from tt).

4. Fill in the squares by combining the allele from the top row with the allele from the left column.

5. The resulting Punnett square looks like this:

   | T | t ---|---|--- t | Tt | tt t | Tt | tt

6. So, the ratio of the progeny is 1 Tt (tall) : 1 tt (short). This means that 50% of the offspring will be heterozygous (Tt) and 50% will be homozygous recessive (tt).