0.15M3 of air is compressed from a pressure of 100kN/M2and a temperature of 20°C to apressure of 1.5MN/M2 according to the law PV1.2=CSketch this on a PV diagram (3 marks)Findi) The work done during compression.Is the work done by or on the gas? (10 marks)ii) The mass of the gas in the cylinder? (5 marks)iii) The change in internal energy (10 marks)iv) The heat transferred during compressionIs this heat supplied or rejected? (5 marks)cv = 7180 J/kgK and R=2870 J/kgK

This is a complex physics problem involving thermodynamics and the behavior of gases. Here's how you can solve it:

i) The work done during compression can be calculated using the formula for work done on an ideal gas during isentropic (constant entropy) compression or expansion, which is:

W = (P2V2 - P1V1) / (n-1)

where P1 and V1 are the initial pressure and volume, P2 and V2 are the final pressure and volume, and n is the polytropic index, which is 1.2 in this case.

The work is done on the gas, because the gas is being compressed.

ii) The mass of the gas in the cylinder can be calculated using the ideal gas law, which is:

PV = mRT

where P is the pressure, V is the volume, m is the mass of the gas, R is the specific gas constant, and T is the temperature. You can rearrange this formula to solve for m:

m = PV / RT

iii) The change in internal energy can be calculated using the first law of thermodynamics, which is:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat transferred, and W is the work done. In this case, you would need to know the heat transferred to calculate the change in internal energy.

iv) The heat transferred during compression can be calculated using the formula:

Q = ΔU + W

where Q is the heat transferred, ΔU is the change in internal energy, and W is the work done. In this case, you would need to know the change in internal energy to calculate the heat transferred.

The heat is supplied to the gas, because the gas is being compressed.

Please note that you would need to convert the units appropriately to use these formulas. Also, these calculations assume that the gas behaves ideally, which may not be the case in reality.

This is a complex physics problem involving the principles of thermodynamics. Here's how you can solve it:

i) The work done during compression can be calculated using the formula for work done on an ideal gas during isentropic (constant entropy) processes:

W = (P2V2 - P1V1) / (n-1)

where P1 and V1 are the initial pressure and volume, P2 and V2 are the final pressure and volume, and n is the polytropic index, which is 1.2 in this case.

The work is done on the gas, as it is being compressed.

ii) The mass of the gas can be calculated using the ideal gas law:

P1V1 = mR*T1

where m is the mass of the gas, R is the specific gas constant, and T1 is the initial temperature in Kelvin. Solve for m.

iii) The change in internal energy can be calculated using the first law of thermodynamics:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat transferred, and W is the work done. However, without knowing the heat transferred, we cannot calculate the change in internal energy.

iv) The heat transferred during compression can be calculated using the first law of thermodynamics:

Q = ΔU + W

However, without knowing the change in internal energy, we cannot calculate the heat transferred.

The heat is supplied to the gas, as it is being compressed.

Please note that the specific heat at constant volume (cv) and the specific gas constant (R) are given, and these can be used in the calculations. The temperature must be converted to Kelvin by adding 273 to the Celsius temperature.