If the seven digit number 4567X75 is divisible by 15 then find the least possible value of X.2103

To find the value of X, we need to know the rules of divisibility by 15. A number is divisible by 15 if it is divisible by both 3 and 5.

1. For a number to be divisible by 5, its last digit must be either 0 or 5. In this case, the last digit is 5, so the number is divisible by 5.

2. For a number to be divisible by 3, the sum of its digits must be divisible by 3.

Let's add the digits of the number: 4 + 5 + 6 + 7 + X + 7 + 5 = 34 + X

For the number to be divisible by 3, the sum (34 + X) must be divisible by 3. The closest multiple of 3 to 34 is 36, so X must be 2 to make the number divisible by 3.

Therefore, the least possible value of X is 2.