Given that the received vector for the (7, 4) code is Y=[1 0 0 1 1 0 1] and H=[1 0 1 1 1 0 0;1 1 0 1 0 1 0;1 1 1 0 0 0 1] . Which of the following is the syndrome vector? [1 0 0] [1 1 0] [1 0 1] [0 1 1]
Question
Given that the received vector for the (7, 4) code is Y=[1 0 0 1 1 0 1] and H=[1 0 1 1 1 0 0;1 1 0 1 0 1 0;1 1 1 0 0 0 1] . Which of the following is the syndrome vector?
[1 0 0]
[1 1 0]
[1 0 1]
[0 1 1]
Solution
To find the syndrome vector, we need to multiply the received vector Y by the transpose of the parity check matrix H. This is done using modulo-2 arithmetic (addition is XOR, multiplication is AND).
The received vector Y is [1 0 0 1 1 0 1].
The parity check matrix H is: [1 0 1 1 1 0 0; 1 1 0 1 0 1 0; 1 1 1 0 0 0 1]
First, transpose the matrix H to get H^T: [1 1 1; 0 1 1; 1 0 1; 1 1 0; 1 0 0; 0 1 0; 0 0 1]
Then, multiply Y by H^T using modulo-2 arithmetic to get the syndrome vector S: S = Y * H^T = [1 0 0 1 1 0 1] * [1 1 1; 0 1 1; 1 0 1; 1 1 0; 1 0 0; 0 1 0; 0 0 1]
Performing the multiplication and addition (remember, addition is XOR, multiplication is AND), we get:
S = [1 XOR 0 XOR 0 XOR 1 XOR 1 XOR 0 XOR 0, 0 XOR 0 XOR 0 XOR 1 XOR 0 XOR 0 XOR 1, 1 XOR 1 XOR 1 XOR 0 XOR 0 XOR 0 XOR 1]
Solving the XOR operations, we get:
S = [1, 0, 0]
So, the syndrome vector is [1 0 0].
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