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Given that the received vector for the (7, 4) code is Y=[1 0 0 1 1 0 1] and H=[1 0 1 1 1 0 0;1 1 0 1 0 1 0;1 1 1 0 0 0 1] . Which of the following is the syndrome vector? [1 0 0] [1 1 0] [1 0 1] [0 1 1]

Question

Given that the received vector for the (7, 4) code is Y=[1 0 0 1 1 0 1] and H=[1 0 1 1 1 0 0;1 1 0 1 0 1 0;1 1 1 0 0 0 1] . Which of the following is the syndrome vector?

[1 0 0]

[1 1 0]

[1 0 1]

[0 1 1]

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Solution

To find the syndrome vector, we need to multiply the received vector Y by the transpose of the parity check matrix H. This is done using modulo-2 arithmetic (addition is XOR, multiplication is AND).

The received vector Y is [1 0 0 1 1 0 1].

The parity check matrix H is: [1 0 1 1 1 0 0; 1 1 0 1 0 1 0; 1 1 1 0 0 0 1]

First, transpose the matrix H to get H^T: [1 1 1; 0 1 1; 1 0 1; 1 1 0; 1 0 0; 0 1 0; 0 0 1]

Then, multiply Y by H^T using modulo-2 arithmetic to get the syndrome vector S: S = Y * H^T = [1 0 0 1 1 0 1] * [1 1 1; 0 1 1; 1 0 1; 1 1 0; 1 0 0; 0 1 0; 0 0 1]

Performing the multiplication and addition (remember, addition is XOR, multiplication is AND), we get:

S = [1 XOR 0 XOR 0 XOR 1 XOR 1 XOR 0 XOR 0, 0 XOR 0 XOR 0 XOR 1 XOR 0 XOR 0 XOR 1, 1 XOR 1 XOR 1 XOR 0 XOR 0 XOR 0 XOR 1]

Solving the XOR operations, we get:

S = [1, 0, 0]

So, the syndrome vector is [1 0 0].

This problem has been solved

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