An airplane passenger carries a 235 N suitcase up the stairs, a displacement of 4.30 m vertically and 4.80 m horizontally.(a) How much work does the passenger do?
Question
An airplane passenger carries a 235 N suitcase up the stairs, a displacement of 4.30 m vertically and 4.80 m horizontally.(a) How much work does the passenger do?
Solution
The work done by a force is given by the equation:
W = F * d * cos(θ)
where: W is the work done, F is the force applied, d is the displacement, and θ is the angle between the force and the displacement.
In this case, the force is the weight of the suitcase, which is 235 N. The displacement is the vertical distance the suitcase is moved, which is 4.30 m. The angle between the force and the displacement is 0 degrees because the force and displacement are in the same direction.
So, the work done by the passenger is:
W = 235 N * 4.30 m * cos(0) W = 235 N * 4.30 m * 1 W = 1010.5 J
So, the passenger does 1010.5 Joules of work.
Similar Questions
Use the following statement to answer questions 7 to 12.A luggage handler pulls a 20.0-kg suitcase up a ramp inclined at above the horizontal by a force of magnitude 140 N that acts parallel to the ramp. The coefficient of kinetic friction between the ramp and the incline is 0.22. The suitcase travels 3.80 m along the ramp.7. Calculate the work done on the suitcase by the force. A. 532 J B. 200J C. 192J D. 350J
QUESTION 8Calculate the work done on the suitcase by the gravitational force. A. 0 B. 280J C. -315J D. -270J
QUESTION 11Calculate the total work done on the suitcase. A. 15J B. 120J C. 0 D. -250J
QUESTION 9Calculate the work done on the suitcase by the normal force. A. 320J B. 0 C. 360J D. 300J
QUESTION 12If the speed of the suitcase is zero at the bottom of the ramp, what is its speed after it has travelled 3.80 m along the ramp? A. 4.00 m/s B. 2.3 m/s C. 7.5 m/s D. 1.2 m/s
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