What is oxidation state of product of alkaline state fussion FeCr2O4 and FeKr2

To determine the oxidation state of the product of the alkaline state fusion of FeCr2O4 and FeKr2, we need to consider the oxidation states of the individual elements involved.

1. FeCr2O4: In FeCr2O4, the oxidation state of Fe (iron) is +2, as it belongs to Group 8 of the periodic table and typically exhibits a +2 oxidation state. The oxidation state of Cr (chromium) can be calculated by assuming the oxidation state of Fe is +2 and the overall charge of the compound is zero. Since there are two Cr atoms, each Cr atom must have an oxidation state of +3 to balance the charges. The oxidation state of O (oxygen) is -2, as it usually exhibits a -2 oxidation state in compounds.

2. FeKr2: In FeKr2, the oxidation state of Fe is +2, as mentioned earlier. The oxidation state of Kr (krypton) is 0, as noble gases are chemically inert and do not typically form compounds or exhibit oxidation states.

Now, let's consider the fusion of these compounds:

FeCr2O4 + FeKr2

Since Fe has the same oxidation state in both compounds (+2), it does not undergo any change in oxidation state during the fusion.

The oxidation state of Cr in FeCr2O4 is +3, while the oxidation state of Kr in FeKr2 is 0. When these compounds fuse, the oxidation state of Cr may change depending on the reaction conditions, but the oxidation state of Kr remains unchanged.

Therefore, without further information about the reaction conditions, it is not possible to determine the exact oxidation state of the product of the alkaline state fusion of FeCr2O4 and FeKr2.