The problem you've described can be solved using a programming language. However, it's important to note that the switch case statement is not typically used to check if a number is even or odd. Instead, it's used to allow a variable to be tested for equality against a list of values.

Here's how you might solve this problem in Java:

```java
import java.util.Scanner;

public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("Enter a number:");
int N = scanner.nextInt();

switch (N % 2) {
case 0:
System.out.println("Even " + (N * N * N));
break;
case 1:
System.out.println("Odd " + (N * N));
break;
}
}
}
```

In this code:

1. We first import the Scanner class, which is used to get user input.
2. We then create a new instance of the Scanner class.
3. We ask the user to enter a number and store this number in the variable `N`.
4. We use a switch statement to check if `N` is even or odd by checking the remainder of `N` divided by 2 (`N % 2`).
5. If `N` is even (`N % 2` is 0), we print "Even" followed by the cube of `N` (`N * N * N`).
6. If `N` is odd (`N % 2` is 1), we print "Odd" followed by the square of `N` (`N * N`).
7. The `break` keyword is used to exit the switch statement after a case has been matched and executed.

Question

The problem you've described can be solved using a programming language. However, it's important to note that the switch case statement is not typically used to check if a number is even or odd. Instead, it's used to allow a variable to be tested for equality against a list of values.

Here's how you might solve this problem in Java:

```java
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("Enter a number:");
        int N = scanner.nextInt();

switch (N % 2) {
            case 0:
                System.out.println("Even " + (N * N * N));
                break;
            case 1:
                System.out.println("Odd " + (N * N));
                break;
        }
    }
}
```

In this code:

1. We first import the Scanner class, which is used to get user input.
2. We then create a new instance of the Scanner class.
3. We ask the user to enter a number and store this number in the variable `N`.
4. We use a switch statement to check if `N` is even or odd by checking the remainder of `N` divided by 2 (`N % 2`).
5. If `N` is even (`N % 2` is 0), we print "Even" followed by the cube of `N` (`N * N * N`).
6. If `N` is odd (`N % 2` is 1), we print "Odd" followed by the square of `N` (`N * N`).
7. The `break` keyword is used to exit the switch statement after a case has been matched and executed.

Knowee AI · Accepted Answer

The problem you've described can be solved using a programming language. However, it's important to note that the switch case statement is not typically used to check if a number is even or odd. Instead, it's used to allow a variable to be tested for equality against a list of values.

Here's how you might solve this problem in Java:

```java
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("Enter a number:");
        int N = scanner.nextInt();

switch (N % 2) {
            case 0:
                System.out.println("Even " + (N * N * N));
                break;
            case 1:
                System.out.println("Odd " + (N * N));
                break;
        }
    }
}
```

In this code:

1. We first import the Scanner class, which is used to get user input.
2. We then create a new instance of the Scanner class.
3. We ask the user to enter a number and store this number in the variable `N`.
4. We use a switch statement to check if `N` is even or odd by checking the remainder of `N` divided by 2 (`N % 2`).
5. If `N` is even (`N % 2` is 0), we print "Even" followed by the cube of `N` (`N * N * N`).
6. If `N` is odd (`N % 2` is 1), we print "Odd" followed by the square of `N` (`N * N`).
7. The `break` keyword is used to exit the switch statement after a case has been matched and executed.

Read a integer number N.Print the cube of N if N is even.Print the square of N if N is odd.Implement the scenario using the switch case statement.Input4OutputEven64

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