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What is the solution to 4(y−3)+19=8(2y+3)+74⁢(𝑦-3)+19=8⁢(2⁢𝑦+3)+7? A. −12-12 B. 1212 C. −2-2 D. 2

Question

What is the solution to 4(y−3)+19=8(2y+3)+74⁢(𝑦-3)+19=8⁢(2⁢𝑦+3)+7? A. −12-12 B. 1212 C. −2-2 D. 2

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Solution

Let's solve the equation step by step:

First, distribute the numbers outside the parentheses:

4(y - 3) + 19 = 8(2y + 3) + 7 becomes 4y - 12 + 19 = 16y + 24 + 7

Simplify the equation:

4y + 7 = 16y + 31

Subtract 4y from both sides:

7 = 12y + 31

Subtract 31 from both sides:

-24 = 12y

Finally, divide both sides by 12 to solve for y:

y = -24 / 12 = -2

So, the solution to the equation is -2 (Option C).

This problem has been solved

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