In Figure, if EC || AB, ∠∠ECD = 70° and ∠∠BDO = 20°, then ∠∠OBD is

Without the figure, it's a bit difficult to provide an accurate answer. However, assuming that OBD is a straight line and D is a point on line OB, we can use the properties of parallel lines and transversal to solve this.

Given: EC || AB, ∠ECD = 70°, ∠BDO = 20°

To find: ∠OBD

Step 1: Since EC || AB and CD is a transversal, by corresponding angles property, ∠ECD = ∠ADB. So, ∠ADB = 70°.

Step 2: Now, ∠ADB and ∠BDO are on a straight line OB. So, by linear pair axiom, ∠ADB + ∠BDO = 180°.

Step 3: Substituting the given values, we get 70° + ∠BDO = 180°.

Step 4: Solving for ∠BDO, we get ∠BDO = 180° - 70° = 110°.

So, ∠OBD = 110°.