Find an equation for the line that passes through the points −6, 1 and 4, 3.

To find the equation of the line that passes through the points (-6,1) and (4,3), we first need to find the slope of the line. The formula for the slope (m) is:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are the coordinates of the two points.

Substituting the given points into the formula, we get:

m = (3 - 1) / (4 - (-6)) = 2 / 10 = 0.2

So, the slope of the line is 0.2.

Next, we use the point-slope form of the line equation, which is:

y - y1 = m(x - x1)

Substituting the slope and one of the points into the equation, we get:

y - 1 = 0.2(x - (-6))

Simplify the equation to get:

y - 1 = 0.2x + 1.2

Finally, solve for y to get the equation of the line in slope-intercept form:

y = 0.2x + 2.2

So, the equation of the line that passes through the points (-6,1) and (4,3) is y = 0.2x + 2.2.