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Car A trails car B by 150 meters. Car B travels at 50km/hr. Car C travels from the opposite direction at 30km/hr. Car C is at a distance of 320 meters from Car B. If car A decides to overtake Car B before cars B and C cross each other, what is the minimum speed at which car A must travel?

Question

Car A trails car B by 150 meters. Car B travels at 50km/hr. Car C travels from the opposite direction at 30km/hr. Car C is at a distance of 320 meters from Car B. If car A decides to overtake Car B before cars B and C cross each other, what is the minimum speed at which car A must travel?

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Solution

To solve this problem, we first need to find out how much time Car B and Car C will take to meet each other.

  1. Convert the speeds of Car B and Car C from km/hr to m/s by multiplying by 5/18. So, the speed of Car B is 50*(5/18) = 13.89 m/s and the speed of Car C is 30*(5/18) = 8.33 m/s.

  2. The total distance between Car B and Car C is 320 meters. When two objects move towards each other, their relative speed is the sum of their individual speeds. So, the relative speed of Car B and Car C is 13.89 + 8.33 = 22.22 m/s.

  3. Time is distance divided by speed. So, the time taken for Car B and Car C to meet is 320 / 22.22 = 14.4 seconds.

  4. In this time, Car B will cover a distance of 14.4 * 13.89 = 200 meters (time*speed).

  5. But Car A is initially 150 meters behind Car B. So, to overtake Car B, Car A needs to cover a total distance of 150 + 200 = 350 meters.

  6. The minimum speed of Car A is therefore 350 / 14.4 = 24.31 m/s.

  7. Convert this speed back to km/hr by multiplying by 18/5. So, the minimum speed of Car A is 24.31 * (18/5) = 87.5 km/hr.

So, Car A must travel at a minimum speed of 87.5 km/hr to overtake Car B before Car B and Car C meet.

This problem has been solved

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