Solve the following quadratic equation for all values of xx in simplest form.4, left bracket, 2, x, minus, 2, right bracket, squared, equals, 164(2x−2) 2 =16
Question
Solve the following quadratic equation for all values of xx in simplest form.4, left bracket, 2, x, minus, 2, right bracket, squared, equals, 164(2x−2) 2 =16
Solution
The equation you provided seems to have a formatting issue. However, I'll assume you meant the equation to be:
4*(2x - 2)^2 = 16
Here are the steps to solve it:
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Divide both sides of the equation by 4 to simplify:
(2x - 2)^2 = 4
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Take the square root of both sides:
2x - 2 = ± √4
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Simplify the right side:
2x - 2 = ± 2
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Solve for x by adding 2 to both sides:
2x = 2 ± 2
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Finally, divide by 2 to isolate x:
x = 1 ± 1
So, the solutions are x = 2 and x = 0.
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