What will be the output of the following C code? #include int main() { int ary[4] = {1, 2, 3, 4}; printf("%d\n", *ary); }a.1b.Compile time errorc.Some garbage valued.Undefined variable

The output of the given C code will be '1'.

Here's the step by step explanation:

1. An array 'ary' of integers is declared and initialized with the values 1, 2, 3, 4.

2. The printf function is used to print the value of '*ary'.

3. In C, the name of the array 'ary' is a pointer to the first element of the array. Therefore, '*ary' is equivalent to 'ary[0]'.

4. Hence, the value '1' which is the first element of the array 'ary' will be printed.

So, the correct answer is a.1.