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For each of the following pdfs let X1, . . . , Xn be iid observations. Find a complete sufficient statistic,or show that one does not exist.(a) f (x; θ) = 2xθ2 , 0 < x < θ, θ > 0(b) f (x; θ) = e−(x−θ) exp (−e−(x−θ)) , −∞ < x < ∞, −∞ < θ < ∞(c) f (x; θ) = (2x)θx(1 − θ)2−x, x = 0, 1, 2, 0 ≤ θ ≤ 1

Question

For each of the following pdfs let X1, . . . , Xn be iid observations. Find a complete sufficient statistic,or show that one does not exist.(a) f (x; θ) = 2xθ2 , 0 < x < θ, θ > 0(b) f (x; θ) = e−(x−θ) exp (−e−(x−θ)) , −∞ < x < ∞, −∞ < θ < ∞(c) f (x; θ) = (2x)θx(1 − θ)2−x, x = 0, 1, 2, 0 ≤ θ ≤ 1

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Solution

(a) For the first pdf, we can use the Factorization Theorem to find a sufficient statistic. The joint pdf of X1, . . . , Xn is given by:

f(x1, ..., xn; θ) = 2^n * θ^(2n) * I(x_(n) ≤ θ)

where x_(n) is the maximum order statistic. The indicator function I(x_(n) ≤ θ) can be factored out, leaving us with a function of θ and T(x) = x_(n), where T(x) is a sufficient statistic for θ.

(b) For the second pdf, we can again use the Factorization Theorem. The joint pdf of X1, . . . , Xn is given by:

f(x1, ..., xn; θ) = exp(-nθ - Σe^(-xi))

This can be factored into a function of θ and T(x) = Σxi and a function of Σe^(-xi). Therefore, T(x) = Σxi is a sufficient statistic for θ.

(c) For the third pdf, it is not possible to factorize the joint pdf into a function of θ and a function of the data that does not depend on θ. Therefore, a sufficient statistic does not exist.

This problem has been solved

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