A bag contains 99 black and 99 red balls. One ball is taken out at random and found to be black. It is kept aside. Another ball is now taken out. What is the probability of taking out a red ball?
Question
A bag contains 99 black and 99 red balls. One ball is taken out at random and found to be black. It is kept aside. Another ball is now taken out. What is the probability of taking out a red ball?
Solution
Sure, here is the step by step solution:
Step 1: Initially, there are 99 black balls and 99 red balls, so the total number of balls is 99 + 99 = 198.
Step 2: One black ball is taken out and kept aside. So, the number of black balls now is 99 - 1 = 98. The total number of balls now is 198 - 1 = 197.
Step 3: Now, we need to find the probability of taking out a red ball. The probability of an event is given by the number of favorable outcomes divided by the total number of outcomes.
Step 4: Here, the favorable outcome is taking out a red ball, and the number of favorable outcomes is the number of red balls, which is 99.
Step 5: The total number of outcomes is the total number of balls, which is now 197.
Step 6: So, the probability of taking out a red ball is 99/197.
Therefore, the probability of taking out a red ball after one black ball has been taken out and kept aside is 99/197.
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