Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC
Question
Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC
Solution
To find the area of a trapezium, we use the formula:
Area = 1/2 * (sum of parallel sides) * height
Here, the parallel sides are AD and BC, and the height is AB. However, we don't know the lengths of AB and BD yet.
First, we need to find the length of BD. We know that the total perimeter of the trapezium is 120 m. So,
BD = Perimeter - (AD + BC + CD) BD = 120 - (40 + 48 + 17) BD = 120 - 105 BD = 15 m
Now, we can find the length of AB using the Pythagorean theorem, since triangle ABD is a right triangle.
AB = sqrt(AD^2 - BD^2) AB = sqrt(40^2 - 15^2) AB = sqrt(1600 - 225) AB = sqrt(1375) AB = 37.08 m (approx)
Now we can find the area of the trapezium:
Area = 1/2 * (AD + BC) * AB Area = 1/2 * (40 + 48) * 37.08 Area = 1/2 * 88 * 37.08 Area = 1631.52 square meters (approx)
So, the area of the trapezium shaped field is approximately 1631.52 square meters.
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