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A steel beam 20 meters long is subjected to a temperature increase of 30°C. If the coefficient of linear expansion for steel is1.2x10⁻⁵/°C, how much does the beam lengthen?Select one:a.7.2mmb.7.2cmc.72mmd.72cm

Question

A steel beam 20 meters long is subjected to a temperature increase of 30°C. If the coefficient of linear expansion for steel is1.2x10⁻⁵/°C, how much does the beam lengthen?Select one:a.7.2mmb.7.2cmc.72mmd.72cm

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Solution

The formula to calculate the change in length due to thermal expansion is:

ΔL = α * L * ΔT

where: ΔL is the change in length, α is the coefficient of linear expansion, L is the original length, and ΔT is the change in temperature.

Substituting the given values into the formula, we get:

ΔL = 1.2x10⁻⁵/°C * 20m * 30°C

Solving this, we get:

ΔL = 0.0072m

Converting this to millimeters (since 1m = 1000mm), we get:

ΔL = 7.2mm

So, the steel beam lengthens by 7.2mm. Therefore, the correct answer is a. 7.2mm.

This problem has been solved

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