An object with a mass M is suspended from an elastic spring with a spring constant k. The object oscillates with maximum amplitude A. If the amplitude of oscillations is doubled, how it will change the period of oscillations.Select one:a. The period remains the sameb. The period is increased by factor fourc. The period is increased by factor twod. The period is decreased by factor twoe. The period is decreased by factor four
Question
An object with a mass M is suspended from an elastic spring with a spring constant k. The object oscillates with maximum amplitude A. If the amplitude of oscillations is doubled, how it will change the period of oscillations.Select one:a. The period remains the sameb. The period is increased by factor fourc. The period is increased by factor twod. The period is decreased by factor twoe. The period is decreased by factor four
Solution
The period of oscillation of an object on a spring is given by the formula T = 2π√(m/k), where m is the mass of the object and k is the spring constant. This formula shows that the period T is independent of the amplitude of the oscillation. Therefore, even if the amplitude is doubled, the period of the oscillation will remain the same. So, the correct answer is:
a. The period remains the same
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