In the mechanism shown on the left, at an instant in time whenOB is vertical its angular velocity is 𝜔 = 1.2 rad/s in thecounter-clockwise direction, and its angular acceleration is 𝛼 =2.4 rad/s2 in the clockwise direction. What is the acceleration ofpoint A at this instant? The length r is 2 m.Useful information: 𝛼⃗ 𝐵/𝐴 = 𝛼⃗𝐴𝐵 × 𝑟⃗𝐵/𝐴 − 𝜔2𝑟⃗𝐵/𝐴Hint: This problem is much easier if you find the instantaneouscentre of zero velocity for AB, in order to calculate 𝜔𝐴𝐵

The triangular plate rotates about a fixed axis through point O. The angular velocity is ω =9 rad/s anti-clockwise and the angular acceleration is α = 2 rad/s2 clockwise. The lengths ofthe vertical side is h = 30 cm and the length of the horizontal side is b = 45 cm.What are the magnitudes of velocity and acceleration of point A at the instant shown

Which of the following expressions gives the instantaneous angular acceleration?

The angular position of a particle as a function of time is given by2 4 7) radian( ) ( stt t+ −=where t is in seconds. Find out the instantaneous angular acceleration of the particle

The angular velocity of a particle is given by ω = 1.5 t – 3t2 + 2, the time when its angular acceleration becomes zeroA 0.1 s B 1 s C 3 s D 0.25 s

wheel rotates around a stationary axis so that the rotation angle φvaries with time asφ = λt2where λ is in rad/s2. Find the total acceleration of the point A at therim at the moment t seconds if the linear velocity of the point A at this moment is v m/s