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n 80 kg man is riding on a small 40 kg cart at a speed of 4 m/s. He jumps off the cart with zero horizontal speed. The final speed of the cart ______(in m/s).

Question

n 80 kg man is riding on a small 40 kg cart at a speed of 4 m/s. He jumps off the cart with zero horizontal speed. The final speed of the cart ______(in m/s).

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Solution

This problem can be solved using the principle of conservation of momentum. The total momentum before the man jumps is equal to the total momentum after he jumps.

Step 1: Calculate the initial momentum The initial momentum (before the man jumps) is the sum of the momentum of the man and the cart. Momentum is calculated as mass times velocity. So, the initial momentum is:

(80 kg * 4 m/s) + (40 kg * 4 m/s) = 320 kgm/s + 160 kgm/s = 480 kg*m/s

Step 2: Calculate the final momentum After the man jumps, he has zero horizontal speed, so his momentum is 0. The final momentum is then just the momentum of the cart. We'll call the final speed of the cart v. So, the final momentum is:

40 kg * v

Step 3: Set the initial momentum equal to the final momentum According to the principle of conservation of momentum, these two should be equal:

480 kg*m/s = 40 kg * v

Step 4: Solve for v Divide both sides by 40 kg to solve for v:

v = 480 kg*m/s / 40 kg = 12 m/s

So, the final speed of the cart is 12 m/s.

This problem has been solved

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