(a) The initial momentum of the car can be found using the formula for momentum, which is mass times velocity. In this case, the mass of the car is 500 kg and the initial velocity is 35 m/s. So, the initial momentum is 500 kg * 35 m/s = 17500 kg*m/s.

(b) The change in momentum of the car can be found by subtracting the final momentum from the initial momentum. The final momentum is the mass of the car times the final velocity, which is 500 kg * 15 m/s = 7500 kg*m/s. So, the change in momentum is 17500 kg*m/s - 7500 kg*m/s = 10000 kg*m/s.

(c) The external force acting on the car can be found using the formula for force, which is change in momentum divided by change in time. The change in momentum is 10000 kg*m/s and the change in time is 2 minutes, which is 120 seconds. So, the external force is 10000 kg*m/s / 120 s = 83.33 N.

(d) The time taken by the car to come to rest from the velocity of 15 m/s can be found using the formula for time, which is change in velocity divided by acceleration. The change in velocity is 15 m/s and the acceleration is the force divided by the mass, which is 50 N / 500 kg = 0.1 m/s^2. So, the time taken is 15 m/s / 0.1 m/s^2 = 150 seconds.

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(a) The initial momentum of the car can be found using the formula for momentum, which is mass times velocity. In this case, the mass of the car is 500 kg and the initial velocity is 35 m/s. So, the initial momentum is 500 kg * 35 m/s = 17500 kg*m/s.

(b) The change in momentum of the car can be found by subtracting the final momentum from the initial momentum. The final momentum is the mass of the car times the final velocity, which is 500 kg * 15 m/s = 7500 kg*m/s. So, the change in momentum is 17500 kg*m/s - 7500 kg*m/s = 10000 kg*m/s.

(c) The external force acting on the car can be found using the formula for force, which is change in momentum divided by change in time. The change in momentum is 10000 kg*m/s and the change in time is 2 minutes, which is 120 seconds. So, the external force is 10000 kg*m/s / 120 s = 83.33 N.

(d) The time taken by the car to come to rest from the velocity of 15 m/s can be found using the formula for time, which is change in velocity divided by acceleration. The change in velocity is 15 m/s and the acceleration is the force divided by the mass, which is 50 N / 500 kg = 0.1 m/s^2. So, the time taken is 15 m/s / 0.1 m/s^2 = 150 seconds.

Knowee AI · Accepted Answer

(a) The initial momentum of the car can be found using the formula for momentum, which is mass times velocity. In this case, the mass of the car is 500 kg and the initial velocity is 35 m/s. So, the initial momentum is 500 kg * 35 m/s = 17500 kg*m/s.

(b) The change in momentum of the car can be found by subtracting the final momentum from the initial momentum. The final momentum is the mass of the car times the final velocity, which is 500 kg * 15 m/s = 7500 kg*m/s. So, the change in momentum is 17500 kg*m/s - 7500 kg*m/s = 10000 kg*m/s.

(c) The external force acting on the car can be found using the formula for force, which is change in momentum divided by change in time. The change in momentum is 10000 kg*m/s and the change in time is 2 minutes, which is 120 seconds. So, the external force is 10000 kg*m/s / 120 s = 83.33 N.

(d) The time taken by the car to come to rest from the velocity of 15 m/s can be found using the formula for time, which is change in velocity divided by acceleration. The change in velocity is 15 m/s and the acceleration is the force divided by the mass, which is 50 N / 500 kg = 0.1 m/s^2. So, the time taken is 15 m/s / 0.1 m/s^2 = 150 seconds.

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