In a box, there are 8 orange, 7 white, and 6 blue balls. If a ball is picked up randomly, what is the probability that it is neither orange nor blue?

To calculate the probability, we first need to know the total number of balls. We add up the orange, white, and blue balls: 8 orange + 7 white + 6 blue = 21 balls in total.

The question asks for the probability of picking a ball that is neither orange nor blue, which means we are only interested in the white balls. There are 7 white balls.

Probability is calculated as the number of desired outcomes (in this case, picking a white ball) divided by the total number of outcomes (picking any ball).

So, the probability of picking a white ball is 7 (white balls) divided by 21 (total balls), which simplifies to 1/3 or approximately 0.3333 when rounded to four decimal places.

So, the probability that the ball picked is neither orange nor blue (i.e., it's white) is 1/3 or 0.3333.

To solve this problem, we need to understand that the probability of an event is calculated by dividing the number of favorable outcomes by the total number of outcomes.

Step 1: Calculate the total number of balls There are 8 orange balls, 7 white balls, and 6 blue balls. So, the total number of balls is 8 + 7 + 6 = 21 balls.

Step 2: Identify the number of favorable outcomes The problem asks for the probability that the ball drawn is neither orange nor blue. The only other color available is white. There are 7 white balls.

Step 3: Calculate the probability The probability is therefore the number of favorable outcomes (white balls) divided by the total number of outcomes (total balls).

So, the probability is 7 (white balls) / 21 (total balls) = 1/3.

Therefore, the probability that the ball drawn is neither orange nor blue is 1/3.