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Ben walks for 83m on a bearing of 111°, and then for 78m on a bearing of 214°.How far is Ben from his starting point?Leave your answer correct to the nearest metre.

Question

Ben walks for 83m on a bearing of 111°, and then for 78m on a bearing of 214°.How far is Ben from his starting point?Leave your answer correct to the nearest metre.

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Solution

To solve this problem, we can use the law of cosines. This law states that for any triangle with sides of lengths a, b, and c, and an angle γ between sides a and b, the following equation holds:

c² = a² + b² - 2ab*cos(γ)

In this case, Ben's two walks form two sides of a triangle, with lengths 83m and 78m. The angle between these two sides is the difference between the two bearings, or 214° - 111° = 103°.

We can now plug these values into the law of cosines to find the length of the third side of the triangle, which is the distance from Ben's starting point:

c² = 83² + 78² - 28378*cos(103°)

Calculating this gives:

c² = 6889 + 6084 - 28378*(-0.173648)

c² = 12973 + 2269.72

c² = 15242.72

Taking the square root of both sides gives the length of the third side:

c = sqrt(15242.72) = 123.46m

Rounding to the nearest meter gives a final answer of 123m. So, Ben is 123m from his starting point.

This problem has been solved

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