Knowee
Questions
Features
Study Tools

Fig. shows a dummy of mass 70 kg used in a crash test to investigate the safety of a new car. The car approaches a solid barrier at 20 m / s. It crashes into the barrier and stops suddenly.Image 1Q 1.2 Calculate the momentum of the dummy immediately before the crash.A 2Words: 0Q 1.3 In the crash test, the passenger compartment comes to rest in 0.20 s.Calculate the deceleration of the passenger compartment.A 2Words: 0Q 1.4The seat belt and airbag bring the dummy to rest so it does not hit the windscreen. The dummy has an average deceleration of 80 m / s2.Calculate the average resultant force applied to the dummy, of mass 70 kg.

Question

Fig. shows a dummy of mass 70 kg used in a crash test to investigate the safety of a new car. The car approaches a solid barrier at 20 m / s. It crashes into the barrier and stops suddenly.Image 1Q 1.2 Calculate the momentum of the dummy immediately before the crash.A 2Words: 0Q 1.3 In the crash test, the passenger compartment comes to rest in 0.20 s.Calculate the deceleration of the passenger compartment.A 2Words: 0Q 1.4The seat belt and airbag bring the dummy to rest so it does not hit the windscreen. The dummy has an average deceleration of 80 m / s2.Calculate the average resultant force applied to the dummy, of mass 70 kg.

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

Q 1.2: The momentum of an object is calculated by the formula: momentum = mass x velocity. Here, the mass of the dummy is 70 kg and the velocity is 20 m/s. So, the momentum would be 70 kg x 20 m/s = 1400 kg m/s.

Q 1.3: Deceleration is the rate of change of velocity. It can be calculated by the formula: deceleration = (final velocity - initial velocity) / time. Here, the final velocity is 0 (as the car comes to rest), the initial velocity is 20 m/s, and the time is 0.20 s. So, the deceleration would be (0 - 20 m/s) / 0.20 s = -100 m/s². The negative sign indicates that it is a deceleration.

Q 1.4: The force applied on an object can be calculated by the formula: force = mass x acceleration. Here, the mass of the dummy is 70 kg and the deceleration (which is a negative acceleration) is 80 m/s². So, the force would be 70 kg x 80 m/s² = 5600 N.

This problem has been solved

Similar Questions

A seat belt holds a 70 kg crash test dummy in the car seat during a collision that slows the car from 90 km/hr to 0 km/hr.  What is the approximate magnitude of the work done by the seat belt on the crash test dummy?A.2,000 JB.20,000 JC.40,000 JD.300,000 J

In the crash test, the passenger compartment comes to rest in 0.20 s.Calculate the deceleration of the passenger compartment

A car of mass 2000 kg which is travelling at 10 m/s crashes into a car of the same mass which is travelling at 5 m/s in the same direction.  Calculate the total momentum of both cars after the collision.10,000 kg m/s40,000 kg m/s20,000 kg m/s30,000 kg m/s2A toy train of mass 0.5 kg which is travelling at 0.5 m/s crashes into a train of mass 1.0 kg which is travelling at 0.25 m/s in the opposite direction.  Upon colliding, the trains stick together.  Calculate their final velocity.0.5 m/s0.33 m/s0.17 m/s0 m/s3A car of mass 1500 kg which is travelling at 10 m/s is involved in a head-on collision with a car of mass 2000 kg which is travelling at 8 m/s.  Upon colliding with one another, both cars stick together.  With what velocity (magnitude and direction) will they move after the collision?8.86 m/s (in the direction in which the 2000 kg car was originally travelling)0.29 m/s (in the direction in which the 2000 kg car was originally travelling)8.86 m/s (in the direction in which the 1500 kg car was originally travelling)0.29 m/s (in the direction in which the 1500 kg car was originally travelling)4An airplane of mass 50,000 kg accelerates along a runway from rest to a velocity of 100 m/s in 20 seconds.  Calculate the average resultant force which was acting on the plane during this time.100,000,000 N250,000 N0.04 N10,000 N5Which of the following is equal to the average resultant force which acts on an object while it is accelerating (or decelerating)?Its change in momentum multiplied by the time for which the force was actingThe time for which the force was acting divided by its change in momentumIts rate of change of momentum (its change in momentum divided by the time for which the force was acting)Its change in momentum (the difference between its initial and final momenta)6The action of a resultant force of 5 kN causes the momentum of a lorry to increase from 100,000 to 120,000 kg m/s.  For how long was this resultant force acting on the lorry?44 seconds4 seconds24 seconds20 seconds

Think about when the car with the crash dummy crashed into the wall. Determine whether the force that the wall applied to the car also applied to the dummy.

The deceleration of the dummy is less than the deceleration of the passenger compartment. Explain why this is of benefit for the safety of a passenger.

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.