If a wire with a cross-sectional area of 0.02 m² experiences a force of 2000 N and stretches by 0.1 meters, what is the Young's modulus of the material?
Question
If a wire with a cross-sectional area of 0.02 m² experiences a force of 2000 N and stretches by 0.1 meters, what is the Young's modulus of the material?
Solution
To calculate the Young's modulus (E) of the material, we can use the formula:
E = (F/A) / (ΔL/L)
where: F is the force applied = 2000 N, A is the cross-sectional area = 0.02 m², ΔL is the change in length = 0.1 m, and L is the original length.
However, we don't have the original length (L) given in the problem. Without this information, we cannot calculate the Young's modulus.
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