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The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction?Choices:- 2/5 7/9 3/11 8/5

Question

The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction?Choices:- 2/5 7/9 3/11 8/5

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Solution

Let's denote the original numerator as x and the denominator as y.

From the problem, we know that:

  1. The numerator is 8 less than the denominator, so we can write this as: x = y - 8

  2. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. We can write this as: (x + 3) / (y - 3) = 3/4

Now we can solve these equations step by step:

First, substitute x from the first equation into the second equation:

(y - 8 + 3) / (y - 3) = 3/4

Simplify this to:

(y - 5) / (y - 3) = 3/4

Cross multiply to get rid of the fraction:

4*(y - 5) = 3*(y - 3)

Expand this to:

4y - 20 = 3y - 9

Rearrange to solve for y:

y = 11

Substitute y = 11 into the first equation to solve for x:

x = 11 - 8 = 3

So, the original fraction is 3/11. Therefore, the correct choice is 3/11.

This problem has been solved

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