he following function reverse() is supposed to reverse a singly linked list. There is one line missing at the end of the function./* Link list node */struct node{ int data; struct node* next;}; /* head_ref is a double pointer which points to head (or start) pointer of linked list */static void reverse(struct node** head_ref){ struct node* prev = NULL; struct node* current = *head_ref; struct node* next; while (current != NULL) { next = current->next; current->next = prev; prev = current; current = next; } /*ADD A STATEMENT HERE*/} What should be added in place of “/*ADD A STATEMENT HERE*/”, so that the function correctly reverses a linked list.
Question
he following function reverse() is supposed to reverse a singly linked list. There is one line missing at the end of the function./* Link list node /struct node{ int data; struct node next;}; /* head_ref is a double pointer which points to head (or start) pointer of linked list /static void reverse(struct node* head_ref){ struct node* prev = NULL; struct node* current = head_ref; struct node next; while (current != NULL) { next = current->next; current->next = prev; prev = current; current = next; } /ADD A STATEMENT HERE/} What should be added in place of “/ADD A STATEMENT HERE/”, so that the function correctly reverses a linked list.
Solution
The missing line of code should be:
*head_ref = prev;
This line of code is necessary to update the head of the linked list to point to the last node visited in the while loop, which is the previous node (prev). This effectively reverses the linked list. Without this line, the head of the linked list would still point to the original first node, which now becomes the last node after the list is reversed, and its next pointer is NULL. This would make all other nodes inaccessible, essentially leaving only one node in the list.
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