What will be the output of the following Python code?a1={3, 4}a2={1, 2}a3=set()j=0k=0for j in a1: for k in a2: a3.add((j,k)) j+=1 k+=1print(a3)Options{(3, 4), (1, 2)}{(4, 2), (3, 1), (4, 1), (5, 2)}{(3, 1), (4, 2)}Error
Question
What will be the output of the following Python code?a1={3, 4}a2={1, 2}a3=set()j=0k=0for j in a1: for k in a2: a3.add((j,k)) j+=1 k+=1print(a3)Options{(3, 4), (1, 2)}{(4, 2), (3, 1), (4, 1), (5, 2)}{(3, 1), (4, 2)}Error
Solution
The output of the given Python code will be {(4, 2), (3, 1), (4, 1), (5, 2)}.
Here's the step by step explanation:
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We have three sets a1, a2, and a3. a1 has elements 3 and 4, a2 has elements 1 and 2, and a3 is an empty set.
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We have two variables j and k, both initialized to 0.
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We start a nested loop where j iterates over the elements of a1 and for each j, k iterates over the elements of a2.
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In the inner loop, we add the tuple (j, k) to the set a3, and then increment both j and k by 1.
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In the first iteration, j is 3 and k is 1, so we add (3, 1) to a3 and then increment j and k to 4 and 2 respectively.
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In the next iteration of the inner loop, j is 4 and k is 2, so
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