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A metal salt solution does not give any precipitate even on excess addition of NH4OH but gives white precipitate on addition of NaOH. The metal salt and white precipitate respectively can bePb(NO3)2 and Pb(OH)2Ca(NO3)2 and Ca(OH)2ZnSO4 and Zn(OH)2MgCl2 and Mg(OH)2

Question

A metal salt solution does not give any precipitate even on excess addition of NH4OH but gives white precipitate on addition of NaOH. The metal salt and white precipitate respectively can bePb(NO3)2 and Pb(OH)2Ca(NO3)2 and Ca(OH)2ZnSO4 and Zn(OH)2MgCl2 and Mg(OH)2

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Solution

The metal salt in question is ZnSO4 and the white precipitate is Zn(OH)2.

Here's the step by step explanation:

  1. The given metal salt solution does not give any precipitate even on excess addition of NH4OH. This rules out Pb(NO3)2 and MgCl2 because lead and magnesium salts would form precipitates with NH4OH.

  2. The solution gives a white precipitate on addition of NaOH. This rules out Ca(NO3)2 because calcium salts are soluble in NaOH and would not form a precipitate.

  3. Therefore, by process of elimination, the metal salt must be ZnSO4. Zinc salts do not form precipitates with NH4OH but do form a white precipitate, Zn(OH)2, with NaOH.

This problem has been solved

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