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What is the output of this C code?#include <stdio.h>int main(){enum {ORANGE = 5, MANGO, BANANA = 4, PEACH};enum {ORANGE = 5, MANGO, BANANA = 4, PEACH};printf("PEACH = %d\n", PEACH); printf("PEACH = %d\n", PEACH); }PEACH = 3PEACH = 4PEACH = 5PEACH = 6

Question

What is the output of this C code?#include <stdio.h>int main(){enum {ORANGE = 5, MANGO, BANANA = 4, PEACH};enum {ORANGE = 5, MANGO, BANANA = 4, PEACH};printf("PEACH = %d\n", PEACH); printf("PEACH = %d\n", PEACH); }PEACH = 3PEACH = 4PEACH = 5PEACH = 6

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Solution

The output of this C code will be:

PEACH = 5 PEACH = 5

Explanation:

In C, an enumeration (enum) is a user-defined data type that consists of integral constants. By default, the first enumerator has the value 0, and the value of each successive enumerator is increased by 1.

In your code, you have two identical enums. In each enum, ORANGE is assigned the value 5. MANGO, which comes after ORANGE, will therefore have the value 6. BANANA is then explicitly assigned the value 4. PEACH, which comes after BANANA, will therefore have the value 5 (one more than BANANA's value).

So, when you print the value of PEACH, it will output 5.

This problem has been solved

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