The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:1520 m22420 m22480 m22520 m2
Question
The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:1520 m22420 m22480 m22520 m2
Solution
To find the area of the rectangle, we need to first determine the length and breadth of the rectangle.
Let's assume the length of the rectangle is L and the breadth is B.
According to the given information, the difference between the length and breadth is 23 m. So, we can write the equation as:
L - B = 23 ----(1)
The perimeter of a rectangle is given by the formula:
Perimeter = 2(L + B)
Substituting the given perimeter value of 206 m, we get:
2(L + B) = 206
Simplifying the equation, we have:
L + B = 103 ----(2)
Now, we have a system of equations (1) and (2) to solve.
To solve the system of equations, we can add equation (1) and equation (2):
(L - B) + (L + B) = 23 + 103
2L = 126
Dividing both sides by 2, we get:
L = 63
Substituting the value of L in equation (2), we can find B:
63 + B = 103
B = 103 - 63
B = 40
Now that we have the length (L = 63) and breadth (B = 40) of the rectangle, we can calculate the area using the formula:
Area = Length x Breadth
Area = 63 x 40
Area = 2520 m^2
Therefore, the area of the rectangle is 2520 m^2.
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